min(by:)
Returns the minimum element in the sequence, using the given predicate as the comparison between elements.
@warn_unqualified_access func min(by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> Self.Element?
Parameters
- areInIncreasingOrder
A predicate that returns
true
if its first argument should be ordered before its second argument; otherwise,false
.
Returns
The sequence’s minimum element, according to areInIncreasingOrder
. If the sequence has no elements, returns nil
.
Overview
The predicate must be a strict weak ordering over the elements. That is, for any elements a
, b
, and c
, the following conditions must hold:
areInIncreasingOrder(a, a)
is alwaysfalse
. (Irreflexivity)If
areInIncreasingOrder(a, b)
andareInIncreasingOrder(b, c)
are bothtrue
, thenareInIncreasingOrder(a, c)
is alsotrue
. (Transitive comparability)Two elements are incomparable if neither is ordered before the other according to the predicate. If
a
andb
are incomparable, andb
andc
are incomparable, thena
andc
are also incomparable. (Transitive incomparability)
This example shows how to use the min(by:)
method on a dictionary to find the key-value pair with the lowest value.
let hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156]
let leastHue = hues.min { a, b in a.value < b.value }
print(leastHue)
// Prints "Optional((key: "Coral", value: 16))"