withUnsafeTemporaryAllocation(byteCount:alignment:_:)
Provides scoped access to a raw buffer pointer with the specified byte count and alignment.
func withUnsafeTemporaryAllocation<R>(byteCount: Int, alignment: Int, _ body: (UnsafeMutableRawBufferPointer) throws -> R) rethrows -> RParameters
- byteCount
The number of bytes to temporarily allocate.
byteCountmust not be negative.- alignment
The alignment of the new, temporary region of allocated memory, in bytes.
alignmentmust be a whole power of 2.- body
A closure to invoke and to which the allocated buffer pointer should be passed.
Returns
Whatever is returned by body.
Overview
This function is useful for cheaply allocating raw storage for a brief duration. Storage may be allocated on the heap or on the stack, depending on the required size and alignment.
When body is called, the contents of the buffer pointer passed to it are in an unspecified, uninitialized state. body is responsible for initializing the buffer pointer before it is used and for deinitializing it before returning, but deallocation is automatic.
The implementation may allocate a larger buffer pointer than is strictly necessary to contain byteCount bytes. The behavior of a program that attempts to access any such additional storage is undefined.
The buffer pointer passed to body (as well as any pointers to elements in the buffer) must not escape. It will be deallocated when body returns and cannot be used afterward.