minAndMax(by:)

Returns both the minimum and maximum elements in the sequence, using the given predicate as the comparison between elements.

MinMax.swift:430
func minAndMax(by areInIncreasingOrder: (Element, Element) throws -> Bool) rethrows -> (min: Element, max: Element)?

Parameters

areInIncreasingOrder

A predicate that returns true if its first argument should be ordered before its second argument; otherwise, false.

Returns

A tuple with the sequence’s minimum element, followed by its maximum element. If the sequence provides multiple qualifying minimum elements, the first equivalent element is returned; of multiple maximum elements, the last is returned. If the sequence has no elements, the method returns nil.

The predicate must be a strict weak ordering over the elements. That is, for any elements a, b, and c, the following conditions must hold:

  • areInIncreasingOrder(a, a) is always false. (Irreflexivity)

  • If areInIncreasingOrder(a, b) and areInIncreasingOrder(b, c) are both true, then areInIncreasingOrder(a, c) is also true. (Transitive comparability)

  • Two elements are incomparable if neither is ordered before the other according to the predicate. If a and b are incomparable, and b and c are incomparable, then a and c are also incomparable. (Transitive incomparability)

This example shows how to use the minAndMax(by:) method on a dictionary to find the key-value pair with the lowest value and the pair with the highest value.

let hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156]
if let extremeHues = hues.minAndMax(by: {$0.value < $1.value}) {
    print(extremeHues.min, extremeHues.max)
} else {
    print("There are no hues")
}
// Prints: "(key: "Coral", value: 16) (key: "Heliotrope", value: 296)"