minAndMax(by:)
Returns both the minimum and maximum elements in the sequence, using the given predicate as the comparison between elements.
func minAndMax(by areInIncreasingOrder: (Element, Element) throws -> Bool) rethrows -> (min: Element, max: Element)?
Parameters
- areInIncreasingOrder
A predicate that returns
true
if its first argument should be ordered before its second argument; otherwise,false
.
Returns
A tuple with the sequence’s minimum element, followed by its maximum element. If the sequence provides multiple qualifying minimum elements, the first equivalent element is returned; of multiple maximum elements, the last is returned. If the sequence has no elements, the method returns nil
.
The predicate must be a strict weak ordering over the elements. That is, for any elements a
, b
, and c
, the following conditions must hold:
areInIncreasingOrder(a, a)
is alwaysfalse
. (Irreflexivity)If
areInIncreasingOrder(a, b)
andareInIncreasingOrder(b, c)
are bothtrue
, thenareInIncreasingOrder(a, c)
is alsotrue
. (Transitive comparability)Two elements are incomparable if neither is ordered before the other according to the predicate. If
a
andb
are incomparable, andb
andc
are incomparable, thena
andc
are also incomparable. (Transitive incomparability)
This example shows how to use the minAndMax(by:)
method on a dictionary to find the key-value pair with the lowest value and the pair with the highest value.
let hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156]
if let extremeHues = hues.minAndMax(by: {$0.value < $1.value}) {
print(extremeHues.min, extremeHues.max)
} else {
print("There are no hues")
}
// Prints: "(key: "Coral", value: 16) (key: "Heliotrope", value: 296)"